2x^2+36x=576

Solution for 2x^2+36x=576 equation:

2x^2+36x=576

We move all terms to the left:

2x^2+36x-(576)=0

a = 2; b = 36; c = -576;
Δ = b2-4ac
Δ = 362-4·2·(-576)
Δ = 5904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5904}=\sqrt{144*41}=\sqrt{144}*\sqrt{41}=12\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{41}}{2*2}=\frac{-36-12\sqrt{41}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{41}}{2*2}=\frac{-36+12\sqrt{41}}{4}
$